1 solutions
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0
#include<bits/stdc++.h> using namespace std; #define int long long int n,a[100004],b[100005],x,y,num=0; signed main(){ cin>>n>>x>>y; num=x; for(int i=0;i<n;i++){ if(num>=y){ cout<<num; return 0; } cin>>a[i]>>b[i]; if(num<a[i]){ cout<<num; return 0; }else{ num-=a[i]; num+=b[i]; } } cout<<num; }
Information
- ID
- 125
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 2
- Tags
- (None)
- # Submissions
- 23
- Accepted
- 8
- Uploaded By