1 solutions

  • 0
    @ 2025-7-19 9:28:58
    #include<bits/stdc++.h>
    using namespace std;
    #define int long long 
    int n,a[100004],b[100005],x,y,num=0;
    signed main(){
    	cin>>n>>x>>y;
    	num=x;
    	for(int i=0;i<n;i++){
    		if(num>=y){
    			cout<<num;
    			return 0;
    		}
    		cin>>a[i]>>b[i];
    		if(num<a[i]){
    			cout<<num;
    			return 0;
    		}else{
    		num-=a[i];
    		num+=b[i];
    		}
    	}
    	cout<<num;
    }
    
    • 1

    Information

    ID
    125
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    2
    Tags
    (None)
    # Submissions
    23
    Accepted
    8
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